labels"
m |
|||
Line 23: | Line 23: | ||
Notice that the key of a property could be name as ''key1.key2'', and EL expressions could retrieve them correctly. | Notice that the key of a property could be name as ''key1.key2'', and EL expressions could retrieve them correctly. | ||
+ | More precisely, ZK groups the segmented labels as map. For example, <code>${labels.app}</code> was resolved as a map containing two entries (<code>title</code> and <tt>description</tt>). | ||
+ | |||
+ | <source lang="xml"> | ||
+ | app.title=Foo | ||
+ | app.description=A super application | ||
+ | </source> | ||
+ | |||
+ | If you have a key named as the prefix of the other keys, you have to use <tt>$</tt> to access it. For example, <tt>${labels.app.$}</tt> is required to resolve the label with key named <tt>app</tt>. | ||
+ | |||
+ | <source lang="xml"> | ||
+ | app=Application | ||
+ | app.title=Foo | ||
+ | app.description=A super application | ||
+ | </source> | ||
<blockquote> | <blockquote> |
Revision as of 07:29, 10 May 2011
labels - java.util.Map
A map of all internationalization labels belonging to the current locale (Locales.getCurrent()).
For example, if you have a properties file as follows:
owner=Foo Inc.
application.name=Killer
application.title=Killer 2011
Then, you could access them with this implicit object as follows.
<grid>
<row>${labels.owner}</row>
<row>${labels.application.name}</row>
<row>${labels.application.title}</row>
</grid>
Notice that the key of a property could be name as key1.key2, and EL expressions could retrieve them correctly.
More precisely, ZK groups the segmented labels as map. For example, ${labels.app}
was resolved as a map containing two entries (title
and description).
app.title=Foo
app.description=A super application
If you have a key named as the prefix of the other keys, you have to use $ to access it. For example, ${labels.app.$} is required to resolve the label with key named app.
app=Application
app.title=Foo
app.description=A super application
Under the hood: The labels object is actually the map returned by Labels.getSegmentedLabels(). Furthermore, if the key of a property contains dot (.), all properties with the same prefix are grouped as another map. For example, ${labels.application} (i.e.,
Labels.getSegmentedLables().get("application")
) will return a map containing two entries (name and title) in the previous example.
Version History
Version | Date | Content |
---|---|---|
5.0.7 | March, 2011 | This implicit object was introduced. |